Solve for x
x=-\frac{3a^{2}}{2}-3
Solve for a (complex solution)
a=-\frac{\sqrt{-6x-18}}{3}
a=\frac{\sqrt{-6x-18}}{3}
Solve for a
a=\frac{\sqrt{-6x-18}}{3}
a=-\frac{\sqrt{-6x-18}}{3}\text{, }x\leq -3
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2x+6=-3a^{2}
Subtract 3a^{2} from both sides. Anything subtracted from zero gives its negation.
2x=-3a^{2}-6
Subtract 6 from both sides.
\frac{2x}{2}=\frac{-3a^{2}-6}{2}
Divide both sides by 2.
x=\frac{-3a^{2}-6}{2}
Dividing by 2 undoes the multiplication by 2.
x=-\frac{3a^{2}}{2}-3
Divide -3a^{2}-6 by 2.
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