Solve 3a=ac+4a+e

$$3 a = a c + 4 a + e$$

Solve for a

$$a=-\frac{e}{c+1}$$

$$c\neq -1$$

Steps for Solving Linear Equation

Subtract ac from both sides.

$$3a-ac=4a+e$$

Subtract 4a from both sides.

$$3a-ac-4a=e$$

Combine 3a and -4a to get -a.

$$-a-ac=e$$

Combine all terms containing a.

$$\left(-1-c\right)a=e$$

The equation is in standard form.

$$\left(-c-1\right)a=e$$

Divide both sides by -1-c.

$$\frac{\left(-c-1\right)a}{-c-1}=\frac{e}{-c-1}$$

Dividing by -1-c undoes the multiplication by -1-c.

$$a=\frac{e}{-c-1}$$

Divide e by -1-c.

$$a=-\frac{e}{c+1}$$

Solve for c

$$c=-\frac{a+e}{a}$$

$$a\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$ac+4a+e=3a$$

Subtract 4a from both sides.

$$ac+e=3a-4a$$

Combine 3a and -4a to get -a.

$$ac+e=-a$$

Subtract e from both sides.

$$ac=-a-e$$

Divide both sides by a.

$$\frac{ac}{a}=\frac{-a-e}{a}$$

Dividing by a undoes the multiplication by a.

$$c=\frac{-a-e}{a}$$

Divide -a-e by a.

$$c=-1-\frac{e}{a}$$