Solve 3a=-b+c

$$3 a = - b + c$$

Solve for a

$$a=\frac{c-b}{3}$$

Steps for Solving Linear Equation

The equation is in standard form.

$$3a=c-b$$

Divide both sides by 3.

$$\frac{3a}{3}=\frac{c-b}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$a=\frac{c-b}{3}$$

Solve for b

$$b=c-3a$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-b+c=3a$$

Subtract c from both sides.

$$-b=3a-c$$

Divide both sides by -1.

$$\frac{-b}{-1}=\frac{3a-c}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$b=\frac{3a-c}{-1}$$

Divide 3a-c by -1.

$$b=c-3a$$