Solve 3a=4/5+bquad[b]

$$3 a = \frac { 4 } { 5 + b } \quad [ b ]$$

Solve for a

$$a=\frac{4b}{3\left(b+5\right)}$$

$$b\neq -5$$

Steps for Solving Linear Equation

Multiply both sides of the equation by b+5.

$$3a\left(b+5\right)=4b$$

Use the distributive property to multiply 3a by b+5.

$$3ab+15a=4b$$

Combine all terms containing a.

$$\left(3b+15\right)a=4b$$

Divide both sides by 3b+15.

$$\frac{\left(3b+15\right)a}{3b+15}=\frac{4b}{3b+15}$$

Dividing by 3b+15 undoes the multiplication by 3b+15.

$$a=\frac{4b}{3b+15}$$

Divide 4b by 3b+15.

$$a=\frac{4b}{3\left(b+5\right)}$$

Solve for b

$$b=\frac{15a}{4-3a}$$

$$a\neq \frac{4}{3}$$

Steps for Solving Linear Equation

Variable b cannot be equal to -5 since division by zero is not defined. Multiply both sides of the equation by b+5.

$$3a\left(b+5\right)=4b$$

Use the distributive property to multiply 3a by b+5.

$$3ab+15a=4b$$

Subtract 4b from both sides.

$$3ab+15a-4b=0$$

Subtract 15a from both sides. Anything subtracted from zero gives its negation.

$$3ab-4b=-15a$$

Combine all terms containing b.

$$\left(3a-4\right)b=-15a$$

Divide both sides by 3a-4.

$$\frac{\left(3a-4\right)b}{3a-4}=-\frac{15a}{3a-4}$$

Dividing by 3a-4 undoes the multiplication by 3a-4.

$$b=-\frac{15a}{3a-4}$$

Variable b cannot be equal to -5.

$$b=-\frac{15a}{3a-4}\text{, }b\neq -5$$