Solve for a
a=-\frac{7c}{3}+3
Solve for c
c=\frac{9-3a}{7}
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3a=9-7c
Subtract 7c from both sides.
\frac{3a}{3}=\frac{9-7c}{3}
Divide both sides by 3.
a=\frac{9-7c}{3}
Dividing by 3 undoes the multiplication by 3.
a=-\frac{7c}{3}+3
Divide 9-7c by 3.
7c=9-3a
Subtract 3a from both sides.
\frac{7c}{7}=\frac{9-3a}{7}
Divide both sides by 7.
c=\frac{9-3a}{7}
Dividing by 7 undoes the multiplication by 7.
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