Solve 3a+4b=6c

$$3 a + 4 b = 6 c$$

Solve for a

$$a=-\frac{4b}{3}+2c$$

Steps for Solving Linear Equation

Subtract 4b from both sides.

$$3a=6c-4b$$

Divide both sides by 3.

$$\frac{3a}{3}=\frac{6c-4b}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$a=\frac{6c-4b}{3}$$

Divide 6c-4b by 3.

$$a=-\frac{4b}{3}+2c$$

Solve for b

$$b=\frac{3c}{2}-\frac{3a}{4}$$

Steps for Solving Linear Equation

Subtract 3a from both sides.

$$4b=6c-3a$$

Divide both sides by 4.

$$\frac{4b}{4}=\frac{6c-3a}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$b=\frac{6c-3a}{4}$$

Divide 6c-3a by 4.

$$b=\frac{3c}{2}-\frac{3a}{4}$$