Solve 3a+4b=12

$$3 a + 4 b = 12$$

Solve for a

$$a=-\frac{4b}{3}+4$$

Steps for Solving Linear Equation

Subtract 4b from both sides.

$$3a=12-4b$$

Divide both sides by 3.

$$\frac{3a}{3}=\frac{12-4b}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$a=\frac{12-4b}{3}$$

Divide 12-4b by 3.

$$a=-\frac{4b}{3}+4$$

Solve for b

$$b=-\frac{3a}{4}+3$$

Steps for Solving Linear Equation

Subtract 3a from both sides.

$$4b=12-3a$$

Divide both sides by 4.

$$\frac{4b}{4}=\frac{12-3a}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$b=\frac{12-3a}{4}$$

Divide 12-3a by 4.

$$b=-\frac{3a}{4}+3$$