Solve 3a+25(2600-a)leq7000

$$3 a + 25 ( 2600 - a ) \leq 7000$$

Solve for a

$$a\geq \frac{29000}{11}$$

Solution Steps

Use the distributive property to multiply 25 by 2600-a.

$$3a+65000-25a\leq 7000$$

Combine 3a and -25a to get -22a.

$$-22a+65000\leq 7000$$

Subtract 65000 from both sides.

$$-22a\leq 7000-65000$$

Subtract 65000 from 7000 to get -58000.

$$-22a\leq -58000$$

Divide both sides by -22. Since -22 is negative, the inequality direction is changed.

$$a\geq \frac{-58000}{-22}$$

Reduce the fraction \frac{-58000}{-22} to lowest terms by extracting and canceling out -2.

$$a\geq \frac{29000}{11}$$