Solve for a
a=-\frac{2c}{3}+3
Solve for c
c=\frac{9-3a}{2}
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3a=9-2c
Subtract 2c from both sides.
\frac{3a}{3}=\frac{9-2c}{3}
Divide both sides by 3.
a=\frac{9-2c}{3}
Dividing by 3 undoes the multiplication by 3.
a=-\frac{2c}{3}+3
Divide 9-2c by 3.
2c=9-3a
Subtract 3a from both sides.
\frac{2c}{2}=\frac{9-3a}{2}
Divide both sides by 2.
c=\frac{9-3a}{2}
Dividing by 2 undoes the multiplication by 2.
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