Solve 3a+2a*5a-7a^2+6a^2/3=

$$3 a + 2 a \cdot 5 a - 7 a ^ { 2 } + \frac { 6 a ^ { 2 } } { 3 } =$$

Evaluate

$$a\left(5a+3\right)$$

Solution Steps

Multiply a and a to get a^{2}.

$$3a+2a^{2}\times 5-7a^{2}+\frac{6a^{2}}{3}$$

Multiply 2 and 5 to get 10.

$$3a+10a^{2}-7a^{2}+\frac{6a^{2}}{3}$$

Combine 10a^{2} and -7a^{2} to get 3a^{2}.

$$3a+3a^{2}+\frac{6a^{2}}{3}$$

Divide 6a^{2} by 3 to get 2a^{2}.

$$3a+3a^{2}+2a^{2}$$

Combine 3a^{2} and 2a^{2} to get 5a^{2}.

$$3a+5a^{2}$$

Factor

$$a\left(5a+3\right)$$

Solution Steps

Factor out a.

$$a\left(3+10a-7a+2a\right)$$

Consider 3+10a-7a+2a. Multiply and combine like terms.

$$5a+3$$

Rewrite the complete factored expression.

$$a\left(5a+3\right)$$