Solve 3a+1/2b=2b

$$3 a + \frac { 1 } { 2 b } = 2 b$$

Solve for a

$$a=\frac{2b}{3}-\frac{1}{6b}$$

$$b\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2b.

$$3a\times 2b+1=2b\times 2b$$

Multiply 3 and 2 to get 6.

$$6ab+1=2b\times 2b$$

Multiply b and b to get b^{2}.

$$6ab+1=2b^{2}\times 2$$

Multiply 2 and 2 to get 4.

$$6ab+1=4b^{2}$$

Subtract 1 from both sides.

$$6ab=4b^{2}-1$$

The equation is in standard form.

$$6ba=4b^{2}-1$$

Divide both sides by 6b.

$$\frac{6ba}{6b}=\frac{4b^{2}-1}{6b}$$

Dividing by 6b undoes the multiplication by 6b.

$$a=\frac{4b^{2}-1}{6b}$$

Divide 4b^{2}-1 by 6b.

$$a=\frac{2b}{3}-\frac{1}{6b}$$

Solve for b

$$b=\frac{\sqrt{9a^{2}+4}+3a}{4}$$

$$b=\frac{-\sqrt{9a^{2}+4}+3a}{4}$$