Solve for N
N=-\frac{Q}{3}+95
Solve for Q
Q=285-3N
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3N=285-Q
Subtract Q from both sides.
\frac{3N}{3}=\frac{285-Q}{3}
Divide both sides by 3.
N=\frac{285-Q}{3}
Dividing by 3 undoes the multiplication by 3.
N=-\frac{Q}{3}+95
Divide 285-Q by 3.
Q=285-3N
Subtract 3N from both sides.
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