Solve for A
A=\frac{3B+1}{4}
Solve for B
B=\frac{4A-1}{3}
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4A-2B-B=1
Combine 3A and A to get 4A.
4A-3B=1
Combine -2B and -B to get -3B.
4A=1+3B
Add 3B to both sides.
4A=3B+1
The equation is in standard form.
\frac{4A}{4}=\frac{3B+1}{4}
Divide both sides by 4.
A=\frac{3B+1}{4}
Dividing by 4 undoes the multiplication by 4.
4A-2B-B=1
Combine 3A and A to get 4A.
4A-3B=1
Combine -2B and -B to get -3B.
-3B=1-4A
Subtract 4A from both sides.
\frac{-3B}{-3}=\frac{1-4A}{-3}
Divide both sides by -3.
B=\frac{1-4A}{-3}
Dividing by -3 undoes the multiplication by -3.
B=\frac{4A-1}{3}
Divide 1-4A by -3.
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