Solve for A
A=\frac{x+3}{15}
Solve for x
x=15A-3
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105A-7x=21
Multiply both sides of the equation by 35, the least common multiple of 5,35.
105A=21+7x
Add 7x to both sides.
105A=7x+21
The equation is in standard form.
\frac{105A}{105}=\frac{7x+21}{105}
Divide both sides by 105.
A=\frac{7x+21}{105}
Dividing by 105 undoes the multiplication by 105.
A=\frac{x}{15}+\frac{1}{5}
Divide 21+7x by 105.
105A-7x=21
Multiply both sides of the equation by 35, the least common multiple of 5,35.
-7x=21-105A
Subtract 105A from both sides.
\frac{-7x}{-7}=\frac{21-105A}{-7}
Divide both sides by -7.
x=\frac{21-105A}{-7}
Dividing by -7 undoes the multiplication by -7.
x=15A-3
Divide 21-105A by -7.
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