Solve 3-yleq4(y-3)

$$3 - y \leq 4 ( y - 3 )$$

Solve for y

$$y\geq 3$$

Solution Steps

Use the distributive property to multiply 4 by y-3.

$$3-y\leq 4y-12$$

Subtract 4y from both sides.

$$3-y-4y\leq -12$$

Combine -y and -4y to get -5y.

$$3-5y\leq -12$$

Subtract 3 from both sides.

$$-5y\leq -12-3$$

Subtract 3 from -12 to get -15.

$$-5y\leq -15$$

Divide both sides by -5. Since -5 is negative, the inequality direction is changed.

$$y\geq \frac{-15}{-5}$$

Divide -15 by -5 to get 3.

$$y\geq 3$$