Solve 3-y=3/4*(2y-1)-2

$$3 - y = \frac { 3 } { 4 } \cdot ( 2 y - 1 ) - 2$$

Solve for y

$$y = \frac{23}{10} = 2\frac{3}{10} = 2.3$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{3}{4} by 2y-1.

$$3-y=\frac{3}{4}\times 2y+\frac{3}{4}\left(-1\right)-2$$

Express \frac{3}{4}\times 2 as a single fraction.

$$3-y=\frac{3\times 2}{4}y+\frac{3}{4}\left(-1\right)-2$$

Multiply 3 and 2 to get 6.

$$3-y=\frac{6}{4}y+\frac{3}{4}\left(-1\right)-2$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$3-y=\frac{3}{2}y+\frac{3}{4}\left(-1\right)-2$$

Multiply \frac{3}{4} and -1 to get -\frac{3}{4}.

$$3-y=\frac{3}{2}y-\frac{3}{4}-2$$

Convert 2 to fraction \frac{8}{4}.

$$3-y=\frac{3}{2}y-\frac{3}{4}-\frac{8}{4}$$

Since -\frac{3}{4} and \frac{8}{4} have the same denominator, subtract them by subtracting their numerators.

$$3-y=\frac{3}{2}y+\frac{-3-8}{4}$$

Subtract 8 from -3 to get -11.

$$3-y=\frac{3}{2}y-\frac{11}{4}$$

Subtract \frac{3}{2}y from both sides.

$$3-y-\frac{3}{2}y=-\frac{11}{4}$$

Combine -y and -\frac{3}{2}y to get -\frac{5}{2}y.

$$3-\frac{5}{2}y=-\frac{11}{4}$$

Subtract 3 from both sides.

$$-\frac{5}{2}y=-\frac{11}{4}-3$$

Convert 3 to fraction \frac{12}{4}.

$$-\frac{5}{2}y=-\frac{11}{4}-\frac{12}{4}$$

Since -\frac{11}{4} and \frac{12}{4} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{5}{2}y=\frac{-11-12}{4}$$

Subtract 12 from -11 to get -23.

$$-\frac{5}{2}y=-\frac{23}{4}$$

Multiply both sides by -\frac{2}{5}, the reciprocal of -\frac{5}{2}.

$$y=-\frac{23}{4}\left(-\frac{2}{5}\right)$$

Multiply -\frac{23}{4} times -\frac{2}{5} by multiplying numerator times numerator and denominator times denominator.

$$y=\frac{-23\left(-2\right)}{4\times 5}$$

Do the multiplications in the fraction \frac{-23\left(-2\right)}{4\times 5}.

$$y=\frac{46}{20}$$

Reduce the fraction \frac{46}{20} to lowest terms by extracting and canceling out 2.

$$y=\frac{23}{10}$$