Solve 3-8*(-1/3)-20+(-1/3)=5*(-1/3)-13

$$3 - 8 \cdot ( - \frac { 1 } { 3 } ) - 20 + ( - \frac { 1 } { 3 } ) = 5 \cdot ( - \frac { 1 } { 3 } ) - 13$$

Verify

Solution Steps

Express 8\left(-\frac{1}{3}\right) as a single fraction.

$$3-\frac{8\left(-1\right)}{3}-20-\frac{1}{3}=5\left(-\frac{1}{3}\right)-13$$

Multiply 8 and -1 to get -8.

$$3-\frac{-8}{3}-20-\frac{1}{3}=5\left(-\frac{1}{3}\right)-13$$

Fraction \frac{-8}{3} can be rewritten as -\frac{8}{3} by extracting the negative sign.

$$3-\left(-\frac{8}{3}\right)-20-\frac{1}{3}=5\left(-\frac{1}{3}\right)-13$$

The opposite of -\frac{8}{3} is \frac{8}{3}.

$$3+\frac{8}{3}-20-\frac{1}{3}=5\left(-\frac{1}{3}\right)-13$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{9}{3}+\frac{8}{3}-20-\frac{1}{3}=5\left(-\frac{1}{3}\right)-13$$

Since \frac{9}{3} and \frac{8}{3} have the same denominator, add them by adding their numerators.

$$\frac{9+8}{3}-20-\frac{1}{3}=5\left(-\frac{1}{3}\right)-13$$

Add 9 and 8 to get 17.

$$\frac{17}{3}-20-\frac{1}{3}=5\left(-\frac{1}{3}\right)-13$$

Convert 20 to fraction \frac{60}{3}.

$$\frac{17}{3}-\frac{60}{3}-\frac{1}{3}=5\left(-\frac{1}{3}\right)-13$$

Since \frac{17}{3} and \frac{60}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{17-60}{3}-\frac{1}{3}=5\left(-\frac{1}{3}\right)-13$$

Subtract 60 from 17 to get -43.

$$-\frac{43}{3}-\frac{1}{3}=5\left(-\frac{1}{3}\right)-13$$

Since -\frac{43}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-43-1}{3}=5\left(-\frac{1}{3}\right)-13$$

Subtract 1 from -43 to get -44.

$$-\frac{44}{3}=5\left(-\frac{1}{3}\right)-13$$

Express 5\left(-\frac{1}{3}\right) as a single fraction.

$$-\frac{44}{3}=\frac{5\left(-1\right)}{3}-13$$

Multiply 5 and -1 to get -5.

$$-\frac{44}{3}=\frac{-5}{3}-13$$

Fraction \frac{-5}{3} can be rewritten as -\frac{5}{3} by extracting the negative sign.

$$-\frac{44}{3}=-\frac{5}{3}-13$$

Convert 13 to fraction \frac{39}{3}.

$$-\frac{44}{3}=-\frac{5}{3}-\frac{39}{3}$$

Since -\frac{5}{3} and \frac{39}{3} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{44}{3}=\frac{-5-39}{3}$$

Subtract 39 from -5 to get -44.

$$-\frac{44}{3}=-\frac{44}{3}$$

Compare -\frac{44}{3} and -\frac{44}{3}.

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