Solve 3-36*(2/9-3/4+1/12)

$$3 - 36 \times ( \frac { 2 } { 9 } - \frac { 3 } { 4 } + \frac { 1 } { 12 } )$$

Evaluate

$$19$$

Solution Steps

Least common multiple of 9 and 4 is 36. Convert \frac{2}{9} and \frac{3}{4} to fractions with denominator 36.

$$3-36\left(\frac{8}{36}-\frac{27}{36}+\frac{1}{12}\right)$$

Since \frac{8}{36} and \frac{27}{36} have the same denominator, subtract them by subtracting their numerators.

$$3-36\left(\frac{8-27}{36}+\frac{1}{12}\right)$$

Subtract 27 from 8 to get -19.

$$3-36\left(-\frac{19}{36}+\frac{1}{12}\right)$$

Least common multiple of 36 and 12 is 36. Convert -\frac{19}{36} and \frac{1}{12} to fractions with denominator 36.

$$3-36\left(-\frac{19}{36}+\frac{3}{36}\right)$$

Since -\frac{19}{36} and \frac{3}{36} have the same denominator, add them by adding their numerators.

$$3-36\times \frac{-19+3}{36}$$

Add -19 and 3 to get -16.

$$3-36\times \frac{-16}{36}$$

Reduce the fraction \frac{-16}{36} to lowest terms by extracting and canceling out 4.

$$3-36\left(-\frac{4}{9}\right)$$

Express 36\left(-\frac{4}{9}\right) as a single fraction.

$$3-\frac{36\left(-4\right)}{9}$$

Multiply 36 and -4 to get -144.

$$3-\frac{-144}{9}$$

Divide -144 by 9 to get -16.

$$3-\left(-16\right)$$

The opposite of -16 is 16.

$$3+16$$

Add 3 and 16 to get 19.

$$19$$

Factor

$$19$$