Solve 3-3*x>4x+3/2

$$3 - 3 \cdot x > \frac { 4 x + 3 } { 2 }$$

Solve for x

$$x<\frac{3}{10}$$

Solution Steps

Multiply both sides of the equation by 2. Since 2 is positive, the inequality direction remains the same.

$$6-6x>4x+3$$

Subtract 4x from both sides.

$$6-6x-4x>3$$

Combine -6x and -4x to get -10x.

$$6-10x>3$$

Subtract 6 from both sides.

$$-10x>3-6$$

Subtract 6 from 3 to get -3.

$$-10x>-3$$

Divide both sides by -10. Since -10 is negative, the inequality direction is changed.

$$x<\frac{-3}{-10}$$

Fraction \frac{-3}{-10} can be simplified to \frac{3}{10} by removing the negative sign from both the numerator and the denominator.

$$x<\frac{3}{10}$$