Solve 3-2(2-4)-(3z-2)=-2-(6z-2)

$$3 - 2 ( 2 - 4 ) - ( 3 z - 2 ) = - 2 - ( 6 z - 2 )$$

Solve for z

$$z=-3$$

Steps for Solving Linear Equation

Subtract 4 from 2 to get -2.

$$3-2\left(-2\right)-\left(3z-2\right)=-2-\left(6z-2\right)$$

Multiply 2 and -2 to get -4.

$$3-\left(-4\right)-\left(3z-2\right)=-2-\left(6z-2\right)$$

The opposite of -4 is 4.

$$3+4-\left(3z-2\right)=-2-\left(6z-2\right)$$

Add 3 and 4 to get 7.

$$7-\left(3z-2\right)=-2-\left(6z-2\right)$$

To find the opposite of 3z-2, find the opposite of each term.

$$7-3z-\left(-2\right)=-2-\left(6z-2\right)$$

The opposite of -2 is 2.

$$7-3z+2=-2-\left(6z-2\right)$$

Add 7 and 2 to get 9.

$$9-3z=-2-\left(6z-2\right)$$

To find the opposite of 6z-2, find the opposite of each term.

$$9-3z=-2-6z-\left(-2\right)$$

The opposite of -2 is 2.

$$9-3z=-2-6z+2$$

Add -2 and 2 to get 0.

$$9-3z=-6z$$

Add 6z to both sides.

$$9-3z+6z=0$$

Combine -3z and 6z to get 3z.

$$9+3z=0$$

Subtract 9 from both sides. Anything subtracted from zero gives its negation.

$$3z=-9$$

Divide both sides by 3.

$$z=\frac{-9}{3}$$

Divide -9 by 3 to get -3.

$$z=-3$$