Solve 3-2div20+10*9

$$3 - 2 \div 20 + 10 \times 9$$

Evaluate

$$\frac{929}{10}=92.9$$

Solution Steps

Reduce the fraction \frac{2}{20} to lowest terms by extracting and canceling out 2.

$$3-\frac{1}{10}+10\times 9$$

Convert 3 to fraction \frac{30}{10}.

$$\frac{30}{10}-\frac{1}{10}+10\times 9$$

Since \frac{30}{10} and \frac{1}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{30-1}{10}+10\times 9$$

Subtract 1 from 30 to get 29.

$$\frac{29}{10}+10\times 9$$

Multiply 10 and 9 to get 90.

$$\frac{29}{10}+90$$

Convert 90 to fraction \frac{900}{10}.

$$\frac{29}{10}+\frac{900}{10}$$

Since \frac{29}{10} and \frac{900}{10} have the same denominator, add them by adding their numerators.

$$\frac{29+900}{10}$$

Add 29 and 900 to get 929.

$$\frac{929}{10}$$

Factor

$$\frac{929}{2 \cdot 5} = 92\frac{9}{10} = 92.9$$