Solve 3-2++n+(-2^2-1-3)

$$3 - 2 + + n + ( - 2 ^ { 2 } - 1 - 3 )$$

Evaluate

$$n-7$$

Solution Steps

Subtract 2 from 3 to get 1.

$$1+n-2^{2}-1-3$$

Calculate 2 to the power of 2 and get 4.

$$1+n-4-1-3$$

Subtract 4 from 1 to get -3.

$$-3+n-1-3$$

Subtract 1 from -3 to get -4.

$$-4+n-3$$

Subtract 3 from -4 to get -7.

$$-7+n$$

Differentiate w.r.t. n

$$1$$

Steps Using Derivative Rule for Sum

Subtract 2 from 3 to get 1.

$$\frac{\mathrm{d}}{\mathrm{d}n}(1+n-2^{2}-1-3)$$

Calculate 2 to the power of 2 and get 4.

$$\frac{\mathrm{d}}{\mathrm{d}n}(1+n-4-1-3)$$

Subtract 4 from 1 to get -3.

$$\frac{\mathrm{d}}{\mathrm{d}n}(-3+n-1-3)$$

Subtract 1 from -3 to get -4.

$$\frac{\mathrm{d}}{\mathrm{d}n}(-4+n-3)$$

Subtract 3 from -4 to get -7.

$$\frac{\mathrm{d}}{\mathrm{d}n}(-7+n)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$n^{1-1}$$

Subtract 1 from 1.

$$n^{0}$$

For any term t except 0, t^{0}=1.

$$1$$