Solve 3-(4*2-5*3)+(-6+3)*8

$$3 - ( 4 \cdot 2 - 5 \cdot 3 ) + ( - 6 + 3 ) \cdot 8$$

Evaluate

$$-14$$

Solution Steps

Multiply 4 and 2 to get 8.

$$3-\left(8-5\times 3\right)+\left(-6+3\right)\times 8$$

Multiply 5 and 3 to get 15.

$$3-\left(8-15\right)+\left(-6+3\right)\times 8$$

Subtract 15 from 8 to get -7.

$$3-\left(-7\right)+\left(-6+3\right)\times 8$$

The opposite of -7 is 7.

$$3+7+\left(-6+3\right)\times 8$$

Add 3 and 7 to get 10.

$$10+\left(-6+3\right)\times 8$$

Add -6 and 3 to get -3.

$$10-3\times 8$$

Multiply -3 and 8 to get -24.

$$10-24$$

Subtract 24 from 10 to get -14.

$$-14$$

Factor

$$-14$$