Solve 3-(5/3-x)=3-4/9x

$$3 - ( \frac { 5 } { 3 } - x ) = 3 - \frac { 4 } { 9 } x$$

Solve for x

$$x = \frac{15}{13} = 1\frac{2}{13} \approx 1.153846154$$

Steps for Solving Linear Equation

To find the opposite of \frac{5}{3}-x, find the opposite of each term.

$$3-\frac{5}{3}-\left(-x\right)=3-\frac{4}{9}x$$

The opposite of -x is x.

$$3-\frac{5}{3}+x=3-\frac{4}{9}x$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{9}{3}-\frac{5}{3}+x=3-\frac{4}{9}x$$

Since \frac{9}{3} and \frac{5}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-5}{3}+x=3-\frac{4}{9}x$$

Subtract 5 from 9 to get 4.

$$\frac{4}{3}+x=3-\frac{4}{9}x$$

Add \frac{4}{9}x to both sides.

$$\frac{4}{3}+x+\frac{4}{9}x=3$$

Combine x and \frac{4}{9}x to get \frac{13}{9}x.

$$\frac{4}{3}+\frac{13}{9}x=3$$

Subtract \frac{4}{3} from both sides.

$$\frac{13}{9}x=3-\frac{4}{3}$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{13}{9}x=\frac{9}{3}-\frac{4}{3}$$

Since \frac{9}{3} and \frac{4}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{13}{9}x=\frac{9-4}{3}$$

Subtract 4 from 9 to get 5.

$$\frac{13}{9}x=\frac{5}{3}$$

Multiply both sides by \frac{9}{13}, the reciprocal of \frac{13}{9}.

$$x=\frac{5}{3}\times \frac{9}{13}$$

Multiply \frac{5}{3} times \frac{9}{13} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{5\times 9}{3\times 13}$$

Do the multiplications in the fraction \frac{5\times 9}{3\times 13}.

$$x=\frac{45}{39}$$

Reduce the fraction \frac{45}{39} to lowest terms by extracting and canceling out 3.

$$x=\frac{15}{13}$$