Solve 3-sqrt{64}+2(3+4^2)*1/2

$$3 - \sqrt { 64 } + 2 ( 3 + 4 ^ { 2 } ) \cdot \frac { 1 } { 2 }$$

Evaluate

$$14$$

Solution Steps

Calculate the square root of 64 and get 8.

$$3-8+2\left(3+4^{2}\right)\times \frac{1}{2}$$

Subtract 8 from 3 to get -5.

$$-5+2\left(3+4^{2}\right)\times \frac{1}{2}$$

Calculate 4 to the power of 2 and get 16.

$$-5+2\left(3+16\right)\times \frac{1}{2}$$

Add 3 and 16 to get 19.

$$-5+2\times 19\times \frac{1}{2}$$

Multiply 2 and 19 to get 38.

$$-5+38\times \frac{1}{2}$$

Multiply 38 and \frac{1}{2} to get \frac{38}{2}.

$$-5+\frac{38}{2}$$

Divide 38 by 2 to get 19.

$$-5+19$$

Add -5 and 19 to get 14.

$$14$$

Factor

$$2\times 7$$