Solve 3-sqrt{49}+2(3+4^2)div1/2

$$3 - \sqrt { 49 } + 2 ( 3 + 4 ^ { 2 } ) \div \frac { 1 } { 2 }$$

Evaluate

$$72$$

Solution Steps

Calculate the square root of 49 and get 7.

$$3-7+\frac{2\left(3+4^{2}\right)}{\frac{1}{2}}$$

Subtract 7 from 3 to get -4.

$$-4+\frac{2\left(3+4^{2}\right)}{\frac{1}{2}}$$

Calculate 4 to the power of 2 and get 16.

$$-4+\frac{2\left(3+16\right)}{\frac{1}{2}}$$

Add 3 and 16 to get 19.

$$-4+\frac{2\times 19}{\frac{1}{2}}$$

Multiply 2 and 19 to get 38.

$$-4+\frac{38}{\frac{1}{2}}$$

Divide 38 by \frac{1}{2} by multiplying 38 by the reciprocal of \frac{1}{2}.

$$-4+38\times 2$$

Multiply 38 and 2 to get 76.

$$-4+76$$

Add -4 and 76 to get 72.

$$72$$

Factor

$$2^{3}\times 3^{2}$$