Solve for x
x\geq \frac{14}{3}
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18-3\left(x-2\right)\leq 6+4
Multiply both sides of the equation by 6, the least common multiple of 2,3. Since 6 is positive, the inequality direction remains the same.
18-3x+6\leq 6+4
Use the distributive property to multiply -3 by x-2.
24-3x\leq 6+4
Add 18 and 6 to get 24.
24-3x\leq 10
Add 6 and 4 to get 10.
-3x\leq 10-24
Subtract 24 from both sides.
-3x\leq -14
Subtract 24 from 10 to get -14.
x\geq \frac{-14}{-3}
Divide both sides by -3. Since -3 is negative, the inequality direction is changed.
x\geq \frac{14}{3}
Fraction \frac{-14}{-3} can be simplified to \frac{14}{3} by removing the negative sign from both the numerator and the denominator.
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