Solve 3-3/2*(-4/7)=2*(-4/7)+5

$$3 - \frac { 3 } { 2 } \cdot ( - \frac { 4 } { 7 } ) = 2 \cdot ( - \frac { 4 } { 7 } ) + 5$$

Verify

Solution Steps

Multiply \frac{3}{2} times -\frac{4}{7} by multiplying numerator times numerator and denominator times denominator.

$$3-\frac{3\left(-4\right)}{2\times 7}=2\left(-\frac{4}{7}\right)+5$$

Do the multiplications in the fraction \frac{3\left(-4\right)}{2\times 7}.

$$3-\frac{-12}{14}=2\left(-\frac{4}{7}\right)+5$$

Reduce the fraction \frac{-12}{14} to lowest terms by extracting and canceling out 2.

$$3-\left(-\frac{6}{7}\right)=2\left(-\frac{4}{7}\right)+5$$

The opposite of -\frac{6}{7} is \frac{6}{7}.

$$3+\frac{6}{7}=2\left(-\frac{4}{7}\right)+5$$

Convert 3 to fraction \frac{21}{7}.

$$\frac{21}{7}+\frac{6}{7}=2\left(-\frac{4}{7}\right)+5$$

Since \frac{21}{7} and \frac{6}{7} have the same denominator, add them by adding their numerators.

$$\frac{21+6}{7}=2\left(-\frac{4}{7}\right)+5$$

Add 21 and 6 to get 27.

$$\frac{27}{7}=2\left(-\frac{4}{7}\right)+5$$

Express 2\left(-\frac{4}{7}\right) as a single fraction.

$$\frac{27}{7}=\frac{2\left(-4\right)}{7}+5$$

Multiply 2 and -4 to get -8.

$$\frac{27}{7}=\frac{-8}{7}+5$$

Fraction \frac{-8}{7} can be rewritten as -\frac{8}{7} by extracting the negative sign.

$$\frac{27}{7}=-\frac{8}{7}+5$$

Convert 5 to fraction \frac{35}{7}.

$$\frac{27}{7}=-\frac{8}{7}+\frac{35}{7}$$

Since -\frac{8}{7} and \frac{35}{7} have the same denominator, add them by adding their numerators.

$$\frac{27}{7}=\frac{-8+35}{7}$$

Add -8 and 35 to get 27.

$$\frac{27}{7}=\frac{27}{7}$$

Compare \frac{27}{7} and \frac{27}{7}.

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