Solve 3-1/6+3/4

$$3 - \frac { 1 } { 6 } + \frac { 3 } { 4 }$$

Evaluate

$$\frac{43}{12}\approx 3.583333333$$

Solution Steps

Convert 3 to fraction \frac{18}{6}.

$$\frac{18}{6}-\frac{1}{6}+\frac{3}{4}$$

Since \frac{18}{6} and \frac{1}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{18-1}{6}+\frac{3}{4}$$

Subtract 1 from 18 to get 17.

$$\frac{17}{6}+\frac{3}{4}$$

Least common multiple of 6 and 4 is 12. Convert \frac{17}{6} and \frac{3}{4} to fractions with denominator 12.

$$\frac{34}{12}+\frac{9}{12}$$

Since \frac{34}{12} and \frac{9}{12} have the same denominator, add them by adding their numerators.

$$\frac{34+9}{12}$$

Add 34 and 9 to get 43.

$$\frac{43}{12}$$

Factor

$$\frac{43}{2 ^ {2} \cdot 3} = 3\frac{7}{12} = 3.5833333333333335$$