Solve 3-1/4y=2x

$$3 - \frac { 1 } { 4 } y = 2 x$$

Solve for x

$$x=-\frac{y}{8}+\frac{3}{2}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$2x=3-\frac{1}{4}y$$

The equation is in standard form.

$$2x=-\frac{y}{4}+3$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{-\frac{y}{4}+3}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{-\frac{y}{4}+3}{2}$$

Divide 3-\frac{y}{4} by 2.

$$x=-\frac{y}{8}+\frac{3}{2}$$

Solve for y

$$y=12-8x$$

Steps for Solving Linear Equation

Subtract 3 from both sides.

$$-\frac{1}{4}y=2x-3$$

Multiply both sides by -4.

$$\frac{-\frac{1}{4}y}{-\frac{1}{4}}=\frac{2x-3}{-\frac{1}{4}}$$

Dividing by -\frac{1}{4} undoes the multiplication by -\frac{1}{4}.

$$y=\frac{2x-3}{-\frac{1}{4}}$$

Divide 2x-3 by -\frac{1}{4} by multiplying 2x-3 by the reciprocal of -\frac{1}{4}.

$$y=12-8x$$