Solve 3-{18x-2-[4x-3+(8x-2)]+3}=8-33

$$3 - \{ 18 x - 2 - [ 4 x - 3 + ( 8 x - 2 ) ] + 3 \} = 8 - 33$$

Solve for x

$$x = \frac{11}{3} = 3\frac{2}{3} \approx 3.666666667$$

Steps for Solving Linear Equation

Combine 4x and 8x to get 12x.

$$3-\left(18x-2-\left(12x-3-2\right)+3\right)=8-33$$

Subtract 2 from -3 to get -5.

$$3-\left(18x-2-\left(12x-5\right)+3\right)=8-33$$

To find the opposite of 12x-5, find the opposite of each term.

$$3-\left(18x-2-12x-\left(-5\right)+3\right)=8-33$$

The opposite of -5 is 5.

$$3-\left(18x-2-12x+5+3\right)=8-33$$

Combine 18x and -12x to get 6x.

$$3-\left(6x-2+5+3\right)=8-33$$

Add -2 and 5 to get 3.

$$3-\left(6x+3+3\right)=8-33$$

Add 3 and 3 to get 6.

$$3-\left(6x+6\right)=8-33$$

To find the opposite of 6x+6, find the opposite of each term.

$$3-6x-6=8-33$$

Subtract 6 from 3 to get -3.

$$-3-6x=8-33$$

Subtract 33 from 8 to get -25.

$$-3-6x=-25$$

Add 3 to both sides.

$$-6x=-25+3$$

Add -25 and 3 to get -22.

$$-6x=-22$$

Divide both sides by -6.

$$x=\frac{-22}{-6}$$

Reduce the fraction \frac{-22}{-6} to lowest terms by extracting and canceling out -2.

$$x=\frac{11}{3}$$