Solve 3-[(13+3*2)div2+5*3]div6=

$$3 - [ ( 13 + 3 \cdot 2 ) \div 2 + 5 \cdot 3 ] \div 6 =$$

Evaluate

$$-\frac{13}{12}\approx -1.083333333$$

Solution Steps

Multiply 3 and 2 to get 6.

$$3-\frac{\frac{13+6}{2}+5\times 3}{6}$$

Add 13 and 6 to get 19.

$$3-\frac{\frac{19}{2}+5\times 3}{6}$$

Multiply 5 and 3 to get 15.

$$3-\frac{\frac{19}{2}+15}{6}$$

Convert 15 to fraction \frac{30}{2}.

$$3-\frac{\frac{19}{2}+\frac{30}{2}}{6}$$

Since \frac{19}{2} and \frac{30}{2} have the same denominator, add them by adding their numerators.

$$3-\frac{\frac{19+30}{2}}{6}$$

Add 19 and 30 to get 49.

$$3-\frac{\frac{49}{2}}{6}$$

Express \frac{\frac{49}{2}}{6} as a single fraction.

$$3-\frac{49}{2\times 6}$$

Multiply 2 and 6 to get 12.

$$3-\frac{49}{12}$$

Convert 3 to fraction \frac{36}{12}.

$$\frac{36}{12}-\frac{49}{12}$$

Since \frac{36}{12} and \frac{49}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{36-49}{12}$$

Subtract 49 from 36 to get -13.

$$-\frac{13}{12}$$

Factor

$$-\frac{13}{12} = -1\frac{1}{12} = -1.0833333333333333$$