Solve 3(y+8)=10(y-4)+8

$$3 ( y + 8 ) = 10 ( y - 4 ) + 8$$

Solve for y

$$y=8$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by y+8.

$$3y+24=10\left(y-4\right)+8$$

Use the distributive property to multiply 10 by y-4.

$$3y+24=10y-40+8$$

Add -40 and 8 to get -32.

$$3y+24=10y-32$$

Subtract 10y from both sides.

$$3y+24-10y=-32$$

Combine 3y and -10y to get -7y.

$$-7y+24=-32$$

Subtract 24 from both sides.

$$-7y=-32-24$$

Subtract 24 from -32 to get -56.

$$-7y=-56$$

Divide both sides by -7.

$$y=\frac{-56}{-7}$$

Divide -56 by -7 to get 8.

$$y=8$$