Solve 3(y+2)-2(2y-3)=12

$$3 ( y + 2 ) - 2 ( 2 y - 3 ) = 12$$

Solve for y

$$y=0$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by y+2.

$$3y+6-2\left(2y-3\right)=12$$

Use the distributive property to multiply -2 by 2y-3.

$$3y+6-4y+6=12$$

Combine 3y and -4y to get -y.

$$-y+6+6=12$$

Add 6 and 6 to get 12.

$$-y+12=12$$

Subtract 12 from both sides.

$$-y=12-12$$

Subtract 12 from 12 to get 0.

$$-y=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since -1 is not equal to 0, y must be equal to 0.

$$y=0$$