Solve 3(x-4)geq5x+3/6

$$3 ( x - 4 ) \geq \frac { 5 x + 3 } { 6 }$$

Solve for x

$$x\geq \frac{75}{13}$$

Solution Steps

Multiply both sides of the equation by 6. Since 6 is positive, the inequality direction remains the same.

$$18\left(x-4\right)\geq 5x+3$$

Use the distributive property to multiply 18 by x-4.

$$18x-72\geq 5x+3$$

Subtract 5x from both sides.

$$18x-72-5x\geq 3$$

Combine 18x and -5x to get 13x.

$$13x-72\geq 3$$

Add 72 to both sides.

$$13x\geq 3+72$$

Add 3 and 72 to get 75.

$$13x\geq 75$$

Divide both sides by 13. Since 13 is positive, the inequality direction remains the same.

$$x\geq \frac{75}{13}$$