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\frac{3\left(x-2\right)^{2}}{3}=\frac{5}{3}
Divide both sides by 3.
\left(x-2\right)^{2}=\frac{5}{3}
Dividing by 3 undoes the multiplication by 3.
x-2=\frac{\sqrt{15}}{3} x-2=-\frac{\sqrt{15}}{3}
Take the square root of both sides of the equation.
x-2-\left(-2\right)=\frac{\sqrt{15}}{3}-\left(-2\right) x-2-\left(-2\right)=-\frac{\sqrt{15}}{3}-\left(-2\right)
Add 2 to both sides of the equation.
x=\frac{\sqrt{15}}{3}-\left(-2\right) x=-\frac{\sqrt{15}}{3}-\left(-2\right)
Subtracting -2 from itself leaves 0.
x=\frac{\sqrt{15}}{3}+2
Subtract -2 from \frac{\sqrt{15}}{3}.
x=-\frac{\sqrt{15}}{3}+2
Subtract -2 from -\frac{\sqrt{15}}{3}.
x=\frac{\sqrt{15}}{3}+2 x=-\frac{\sqrt{15}}{3}+2
The equation is now solved.