Solve 3(x-1)+5leq5(x+2)

$$3 ( x - 1 ) + 5 \leq 5 ( x + 2 )$$

Solve for x

$$x\geq -4$$

Solution Steps

Use the distributive property to multiply 3 by x-1.

$$3x-3+5\leq 5\left(x+2\right)$$

Add -3 and 5 to get 2.

$$3x+2\leq 5\left(x+2\right)$$

Use the distributive property to multiply 5 by x+2.

$$3x+2\leq 5x+10$$

Subtract 5x from both sides.

$$3x+2-5x\leq 10$$

Combine 3x and -5x to get -2x.

$$-2x+2\leq 10$$

Subtract 2 from both sides.

$$-2x\leq 10-2$$

Subtract 2 from 10 to get 8.

$$-2x\leq 8$$

Divide both sides by -2. Since -2 is negative, the inequality direction is changed.

$$x\geq \frac{8}{-2}$$

Divide 8 by -2 to get -4.

$$x\geq -4$$