Solve 3(x+2y)quady=3

$$3 ( x + 2 y ) \quad y = 3$$

Solve for x

$$x=-2y+\frac{1}{y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by x+2y.

$$\left(3x+6y\right)y=3$$

Use the distributive property to multiply 3x+6y by y.

$$3xy+6y^{2}=3$$

Subtract 6y^{2} from both sides.

$$3xy=3-6y^{2}$$

The equation is in standard form.

$$3yx=3-6y^{2}$$

Divide both sides by 3y.

$$\frac{3yx}{3y}=\frac{3-6y^{2}}{3y}$$

Dividing by 3y undoes the multiplication by 3y.

$$x=\frac{3-6y^{2}}{3y}$$

Divide 3-6y^{2} by 3y.

$$x=-2y+\frac{1}{y}$$

Solve for y

$$y=\frac{\sqrt{x^{2}+8}-x}{4}$$

$$y=\frac{-\sqrt{x^{2}+8}-x}{4}$$