Solve 3(x+2)^2+4=13

$$3 ( x + 2 ) ^ { 2 } + 4 = 13$$

Solve for x

$$x=\sqrt{3}-2\approx -0.267949192$$

$$x=-\left(\sqrt{3}+2\right)\approx -3.732050808$$

Steps by Finding Square Root

Subtract 4 from both sides of the equation.

$$3\left(x+2\right)^{2}+4-4=13-4$$

Subtracting 4 from itself leaves 0.

$$3\left(x+2\right)^{2}=13-4$$

Subtract 4 from 13.

$$3\left(x+2\right)^{2}=9$$

Divide both sides by 3.

$$\frac{3\left(x+2\right)^{2}}{3}=\frac{9}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$\left(x+2\right)^{2}=\frac{9}{3}$$

Divide 9 by 3.

$$\left(x+2\right)^{2}=3$$

Take the square root of both sides of the equation.

$$x+2=\sqrt{3} x+2=-\sqrt{3}$$

Subtract 2 from both sides of the equation.

$$x+2-2=\sqrt{3}-2 x+2-2=-\sqrt{3}-2$$

Subtracting 2 from itself leaves 0.

$$x=\sqrt{3}-2 x=-\sqrt{3}-2$$