Solve 3(x+1)^2=7

$$3 ( x + 1 ) ^ { 2 } = 7$$

Solve for x

$$x=\frac{\sqrt{21}}{3}-1\approx 0.527525232$$

$$x=-\frac{\sqrt{21}}{3}-1\approx -2.527525232$$

Steps by Finding Square Root

Divide both sides by 3.

$$\frac{3\left(x+1\right)^{2}}{3}=\frac{7}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$\left(x+1\right)^{2}=\frac{7}{3}$$

Take the square root of both sides of the equation.

$$x+1=\frac{\sqrt{21}}{3} x+1=-\frac{\sqrt{21}}{3}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{\sqrt{21}}{3}-1 x+1-1=-\frac{\sqrt{21}}{3}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{\sqrt{21}}{3}-1 x=-\frac{\sqrt{21}}{3}-1$$