Solve 3(x+1)<-4

$$3 ( x + 1 ) < - 4$$

Solve for x

$$x<-\frac{7}{3}$$

Solution Steps

Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$x+1<-\frac{4}{3}$$

Subtract 1 from both sides.

$$x<-\frac{4}{3}-1$$

Convert 1 to fraction \frac{3}{3}.

$$x<-\frac{4}{3}-\frac{3}{3}$$

Since -\frac{4}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$x<\frac{-4-3}{3}$$

Subtract 3 from -4 to get -7.

$$x<-\frac{7}{3}$$