Solve 3(p^2)^-3*4p+6p^0

$$3 ( p ^ { 2 } ) ^ { - 3 } \times 4 p + 6 p ^ { 0 }$$

Evaluate

$$6+\frac{12}{p^{5}}$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and -3 to get -6.

$$3p^{-6}\times 4p+6p^{0}$$

To multiply powers of the same base, add their exponents. Add -6 and 1 to get -5.

$$3p^{-5}\times 4+6p^{0}$$

Multiply 3 and 4 to get 12.

$$12p^{-5}+6p^{0}$$

Calculate p to the power of 0 and get 1.

$$12p^{-5}+6\times 1$$

Multiply 6 and 1 to get 6.

$$12p^{-5}+6$$

Factor

$$\frac{6\left(p^{5}+2\right)}{p^{5}}$$