Solve for n
n=2x+\frac{7}{3}
Solve for x
x=\frac{n}{2}-\frac{7}{6}
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n-2x=\frac{7}{3}
Divide both sides by 3.
n=\frac{7}{3}+2x
Add 2x to both sides.
n-2x=\frac{7}{3}
Divide both sides by 3.
-2x=\frac{7}{3}-n
Subtract n from both sides.
\frac{-2x}{-2}=\frac{\frac{7}{3}-n}{-2}
Divide both sides by -2.
x=\frac{\frac{7}{3}-n}{-2}
Dividing by -2 undoes the multiplication by -2.
x=\frac{n}{2}-\frac{7}{6}
Divide \frac{7}{3}-n by -2.
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