Solve 3(n-1/12)-3/4

$$3 ( n - \frac { 1 } { 12 } ) - \frac { 3 } { 4 }$$

Evaluate

$$3n-1$$

Solution Steps

Use the distributive property to multiply 3 by n-\frac{1}{12}.

$$3n+3\left(-\frac{1}{12}\right)-\frac{3}{4}$$

Express 3\left(-\frac{1}{12}\right) as a single fraction.

$$3n+\frac{3\left(-1\right)}{12}-\frac{3}{4}$$

Multiply 3 and -1 to get -3.

$$3n+\frac{-3}{12}-\frac{3}{4}$$

Reduce the fraction \frac{-3}{12} to lowest terms by extracting and canceling out 3.

$$3n-\frac{1}{4}-\frac{3}{4}$$

Since -\frac{1}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$3n+\frac{-1-3}{4}$$

Subtract 3 from -1 to get -4.

$$3n+\frac{-4}{4}$$

Divide -4 by 4 to get -1.

$$3n-1$$

Expand

$$3n-1$$

Solution Steps

Use the distributive property to multiply 3 by n-\frac{1}{12}.

$$3n+3\left(-\frac{1}{12}\right)-\frac{3}{4}$$

Express 3\left(-\frac{1}{12}\right) as a single fraction.

$$3n+\frac{3\left(-1\right)}{12}-\frac{3}{4}$$

Multiply 3 and -1 to get -3.

$$3n+\frac{-3}{12}-\frac{3}{4}$$

Reduce the fraction \frac{-3}{12} to lowest terms by extracting and canceling out 3.

$$3n-\frac{1}{4}-\frac{3}{4}$$

Since -\frac{1}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$3n+\frac{-1-3}{4}$$

Subtract 3 from -1 to get -4.

$$3n+\frac{-4}{4}$$

Divide -4 by 4 to get -1.

$$3n-1$$