Solve 3(k+1)(2k+4)(k-1)

$$3 ( k + 1 ) ( 2 k + 4 ) ( k - 1 )$$

Evaluate

$$6\left(k+2\right)\left(k^{2}-1\right)$$

Solution Steps

Use the distributive property to multiply 3 by k+1.

$$\left(3k+3\right)\left(2k+4\right)\left(k-1\right)$$

Apply the distributive property by multiplying each term of 3k+3 by each term of 2k+4.

$$\left(6k^{2}+12k+6k+12\right)\left(k-1\right)$$

Combine 12k and 6k to get 18k.

$$\left(6k^{2}+18k+12\right)\left(k-1\right)$$

Apply the distributive property by multiplying each term of 6k^{2}+18k+12 by each term of k-1.

$$6k^{3}-6k^{2}+18k^{2}-18k+12k-12$$

Combine -6k^{2} and 18k^{2} to get 12k^{2}.

$$6k^{3}+12k^{2}-18k+12k-12$$

Combine -18k and 12k to get -6k.

$$6k^{3}+12k^{2}-6k-12$$

Expand

$$6k^{3}+12k^{2}-6k-12$$

Solution Steps

Use the distributive property to multiply 3 by k+1.

$$\left(3k+3\right)\left(2k+4\right)\left(k-1\right)$$

Apply the distributive property by multiplying each term of 3k+3 by each term of 2k+4.

$$\left(6k^{2}+12k+6k+12\right)\left(k-1\right)$$

Combine 12k and 6k to get 18k.

$$\left(6k^{2}+18k+12\right)\left(k-1\right)$$

Apply the distributive property by multiplying each term of 6k^{2}+18k+12 by each term of k-1.

$$6k^{3}-6k^{2}+18k^{2}-18k+12k-12$$

Combine -6k^{2} and 18k^{2} to get 12k^{2}.

$$6k^{3}+12k^{2}-18k+12k-12$$

Combine -18k and 12k to get -6k.

$$6k^{3}+12k^{2}-6k-12$$