Solve for b
b=9
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3b+3=2\left(b+6\right)
Use the distributive property to multiply 3 by b+1.
3b+3=2b+12
Use the distributive property to multiply 2 by b+6.
3b+3-2b=12
Subtract 2b from both sides.
b+3=12
Combine 3b and -2b to get b.
b=12-3
Subtract 3 from both sides.
b=9
Subtract 3 from 12 to get 9.
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