Solve 3(a-b)^2

$$3 ( a - b ) ^ { 2 }$$

Expand

$$3a^{2}-6ab+3b^{2}$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(a-b\right)^{2}.

$$3\left(a^{2}-2ab+b^{2}\right)$$

Use the distributive property to multiply 3 by a^{2}-2ab+b^{2}.

$$3a^{2}-6ab+3b^{2}$$

Evaluate

$$3\left(a-b\right)^{2}$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(a-b\right)^{2}.

$$3\left(a^{2}-2ab+b^{2}\right)$$

Use the distributive property to multiply 3 by a^{2}-2ab+b^{2}.

$$3a^{2}-6ab+3b^{2}$$