Solve 3(a+8)=6(a+4)-3a

$$3 ( a + 8 ) = 6 ( a + 4 ) - 3 a$$

Solve for a (complex solution)

$$a\in \mathrm{C}$$

Solution Steps

Use the distributive property to multiply 3 by a+8.

$$3a+24=6\left(a+4\right)-3a$$

Use the distributive property to multiply 6 by a+4.

$$3a+24=6a+24-3a$$

Combine 6a and -3a to get 3a.

$$3a+24=3a+24$$

Subtract 3a from both sides.

$$3a+24-3a=24$$

Combine 3a and -3a to get 0.

$$24=24$$

Compare 24 and 24.

$$\text{true}$$

This is true for any a.

$$a\in \mathrm{C}$$

Solve for a

$$a\in \mathrm{R}$$

Solution Steps

Use the distributive property to multiply 3 by a+8.

$$3a+24=6\left(a+4\right)-3a$$

Use the distributive property to multiply 6 by a+4.

$$3a+24=6a+24-3a$$

Combine 6a and -3a to get 3a.

$$3a+24=3a+24$$

Subtract 3a from both sides.

$$3a+24-3a=24$$

Combine 3a and -3a to get 0.

$$24=24$$

Compare 24 and 24.

$$\text{true}$$

This is true for any a.

$$a\in \mathrm{R}$$