Solve 3(6r-5)+2r=3(r-5)-5r

$$3 ( 6 r - 5 ) + 2 r = 3 ( r - 5 ) - 5 r$$

Solve for r

$$r=0$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by 6r-5.

$$18r-15+2r=3\left(r-5\right)-5r$$

Combine 18r and 2r to get 20r.

$$20r-15=3\left(r-5\right)-5r$$

Use the distributive property to multiply 3 by r-5.

$$20r-15=3r-15-5r$$

Combine 3r and -5r to get -2r.

$$20r-15=-2r-15$$

Add 2r to both sides.

$$20r-15+2r=-15$$

Combine 20r and 2r to get 22r.

$$22r-15=-15$$

Add 15 to both sides.

$$22r=-15+15$$

Add -15 and 15 to get 0.

$$22r=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since 22 is not equal to 0, r must be equal to 0.

$$r=0$$