Solve 3(3-x)-7>5(x+8)

$$3 ( 3 - x ) - 7 > 5 ( x + 8 )$$

Solve for x

$$x<-\frac{19}{4}$$

Solution Steps

Use the distributive property to multiply 3 by 3-x.

$$9-3x-7>5\left(x+8\right)$$

Subtract 7 from 9 to get 2.

$$2-3x>5\left(x+8\right)$$

Use the distributive property to multiply 5 by x+8.

$$2-3x>5x+40$$

Subtract 5x from both sides.

$$2-3x-5x>40$$

Combine -3x and -5x to get -8x.

$$2-8x>40$$

Subtract 2 from both sides.

$$-8x>40-2$$

Subtract 2 from 40 to get 38.

$$-8x>38$$

Divide both sides by -8. Since -8 is negative, the inequality direction is changed.

$$x<\frac{38}{-8}$$

Reduce the fraction \frac{38}{-8} to lowest terms by extracting and canceling out 2.

$$x<-\frac{19}{4}$$